Metric Conversion Forum

...fahrenheit.?

zero

- 40 for F and C. Kelvin is different

kelvin is never the same but -40 for C and F

The is no multiplication or division factor between Kelvins and the Celsius scale. You simply add 273.15 to a Kelvin reading to get the Celsius value. You have to use a conversion factor between Celsius and Fahrenheit and between Kelvin and Fahrenheit, you have to first convert Kelvins to degrees Celsius to then convert to degrees Fahrenheit.Ah sorry, misunderstood the question...cheerio!

its not 0 which is 32 in farinhit and 273 or something like that kalvin i dont think any of them have the same temp point be kalvain is always celsius - 273 so that would be impossible to ever have them = the same thing

there is no temperature the with the same numerical value in all scales. kelvin is ALWAYS 273 higher thancelcius.maybe the answer to your question is infinity that is a numerical value but it is not defined so thats my best guess! i cant type what it looks like on this site out but im sure you can find it on the internet

it should be kelvin and fahrenheit........dat it mike..........

Yes -40 ºF=-40 ºCalso 574.6 K = 574.6 ºFKelvin and ºC can never be the same as K-273.15 = ºC

Your question says both scales but you list 3It is impossible to have a tempereature that is the same in all 3.  I believe that to convert from K to C you add 373.-40 is the same in both C and F

For Celsius and Fahrenheit, the answer is -40°.  Remember that the equation to convert Celsius to Fahrenheit is:C = (9/5 * F) + 32If we want C = F, then:C = (9/5 * C) + 32C - 32 = 9/5 * C-32 = 4/5 * C(5/4) * -32 = C = -40 = FThe Fahrenheit scale can also have an equivalent point with Kelvin, as deflagrated mentioned above:K = C + 273.16 = [5/9 * (F-32)] + 273.16If we want K = F, then:K = [5/9 * (K-32)] + 273.16K = (5/9 * K) - (5/9 * 32) + 273.164/9 * K = -(5/9 * 32) + 273.164/9 * K = -17.78 + 273.16 = 255.38K = F = 574.61°The Kelvin (K) scale is related to the Celsius scale, but the zero point, instead of being at the freezing point of water, is based on the extrapolated value for Absolute Zero -- the temperature at which all atomic & molecular motions cease.  0°K = -273.16°C.For the Fahrenheit scale, there is an equivalent absolute scale called the Rankin (R) scale.  0° Rankin = -459.69°FThe absolute scales, Kelvin and Rankin, are only equal at 0°.  For every degree increase in K, you increase R by 1.8°, so they will never be equal again until you reach infinity.So, the only possible point at which all four of the temperature scales can possibly be equal is at infinity.